Question 121: Dual Nature of Matter and Radiation

Question

Let K
1
and K
2
be the maximum kinetic energies of photo-electrons emitted when two monochromatic beams of wavelength $$\lambda$$
1
and $$\lambda$$
2
, respectively are incident on a metallic surface. If $$\lambda$$
1
= 3$$\lambda$$
2
then :

Accepted Answer

$${K_1} = {{hc} \over {{\lambda _1}}} - \phi  = {{hc} \over {3{\lambda _2}}} - \phi $$ ..... (i)
and $${K_2} = {{hc} \over {{\lambda _2}}} - \phi $$ ..... (ii)
from (i) and (ii) we can say
$$3{K_1} = {K_2} - 2\phi $$
$${K_1} < {{{K_2}} \over 3}$$

Answer

$${K_1} > {{{K_2}} \over 3}$$

Answer

$${K_1} < {{{K_2}} \over 3}$$

Answer

$${K_1} = {{{K_2}} \over 3}$$

Answer

$${K_2} = {{{K_1}} \over 3}$$

Dual Nature of Matter and Radiation

Let K 1 and K 2 be the maximum kinetic energies of photo-electrons emitted when two monochromatic beams of wavelength $\lambda 1 and \lambda 2 , respectively are incident on a metallic surface. If \lambda 1 = 3\lambda$ 2 then :

Choose the correct answer: