Question 242: Dual Nature of Matter and Radiation

Question

The graph shows the variation of photocurrent with anode potential for four different radiations. Let $\mathrm{I}_{\mathrm{a}}, \mathrm{I}_{\mathrm{b}}, \mathrm{I}_{\mathrm{c}}$ and $\mathrm{I}_{\mathrm{d}}$ are intensities and $\mathrm{f}_{\mathrm{a}}, \mathrm{f}_{\mathrm{b}}, \mathrm{f}_{\mathrm{c}}$ and $\mathrm{f}_{\mathrm{d}}$ be the frequencies for the curves $\mathrm{a}, \mathrm{b}, \mathrm{c}$ and d respectively, then

Accepted Answer

We know stopping potential is directly proportional to the frequency of the incoming radiation.
$$ 	herefore \quad \mathrm{f}_{\mathrm{b}}>\mathrm{f}_{\mathrm{a}}, \mathrm{f}_{\mathrm{b}}=\mathrm{f}_{\mathrm{c}} $$
Saturation current for $c$ and $d$ is same, hence intensity
$$ \mathrm{I}_{\mathrm{c}}=\mathrm{I}_{\mathrm{d}} $$

Answer

$\mathrm{f}_{\mathrm{b}}>\mathrm{f}_{\mathrm{a}}, \mathrm{f}_{\mathrm{b}}=\mathrm{f}_{\mathrm{c}}, \mathrm{I}_{\mathrm{c}}=\mathrm{I}_{\mathrm{d}}$

Answer

$\mathrm{f}_{\mathrm{b}}=\mathrm{f}_{\mathrm{a}}, \mathrm{f}_{\mathrm{b}}>\mathrm{f}_{\mathrm{c}}, \mathrm{I}_{\mathrm{c}}>\mathrm{I}_{\mathrm{d}}$

Answer

$\mathrm{f}_{\mathrm{b}}<\mathrm{f}_{\mathrm{a}}, \mathrm{f}_{\mathrm{b}}<\mathrm{f}_{\mathrm{c}}, \mathrm{I}_{\mathrm{c}}<\mathrm{I}_{\mathrm{d}}$

Answer

$\mathrm{f}_{\mathrm{b}}<\mathrm{f}_{\mathrm{a}}, \mathrm{f}_{\mathrm{b}}>\mathrm{f}_{\mathrm{c}}, \mathrm{I}_{\mathrm{c}}=\mathrm{I}_{\mathrm{d}}$

Dual Nature of Matter and Radiation

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