Question 140: Dual Nature of Matter and Radiation

Question

What should be the order of arrangement of de-Broglie wavelength of electron ($$\lambda$$
e
), an $$\alpha$$-particle ($$\lambda$$
a
) and proton ($$\lambda$$
p
) given that all have the same kinetic energy?

Accepted Answer

$$\lambda  = {h \over p} = {h \over {\sqrt {2mE} }} \propto {1 \over {\sqrt m }}$$
m
$$\alpha$$
> m
p
> m
e
So, $$\lambda$$
e
> $$\lambda$$
p
> $$\lambda$$
$$\alpha$$

Answer

$$\lambda$$
e
= $$\lambda$$
p
= $$\lambda$$
$$\alpha$$

Answer

$$\lambda$$
e
< $$\lambda$$
p
< $$\lambda$$
$$\alpha$$

Answer

$$\lambda$$
e
> $$\lambda$$
p
> $$\lambda$$
$$\alpha$$

Answer

$$\lambda$$
e
= $$\lambda$$
p
> $$\lambda$$
$$\alpha$$

Dual Nature of Matter and Radiation

What should be the order of arrangement of de-Broglie wavelength of electron ($\lambda e ), an \alpha-particle (\lambda a ) and proton (\lambda$ p ) given that all have the same kinetic energy?

Choose the correct answer: