Question 184: Dual Nature of Matter and Radiation

Question

If the de Broglie wavelength of an electron is equal to the 10
–3
times the wavelength of a photon of  frequency 6 $$ 	imes $$ 10
14
Hz, then the speed of electron is equal to : (Speed of light = 3 $$ 	imes $$ 10
8
m/s, Planck's constant = 6.63 $$ 	imes $$
10
–34
J.s, Mass of electron = 9.1 $$ 	imes $$ 10
–31
kg)

Accepted Answer

$${h \over {mv}} = {10^{ - 3}}\left( {{{3 	imes {{10}^8}} \over {6 	imes {{10}^{14}}}}} ight)$$
v $$ = {{6.63 	imes {{10}^{ - 34}} 	imes 6 	imes {{10}^{14}}} \over {9.1 	imes {{10}^{ - 31}} 	imes 3 	imes {{10}^5}}}$$
v $$ = 1.45 	imes {10^6}$$ m/s

Answer

1.7 $$ 	imes $$ 10
6
m/s

Answer

1.45 $$ 	imes $$ 10
6
m/s

Answer

1.1 $$ 	imes $$ 10
6
m/s

Answer

1.8 $$ 	imes $$ 10
6
m/s

Dual Nature of Matter and Radiation

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