Question 292: Electromagnetic Induction

Question

The magnetic flux through a coil of resistance '$R$' changes by an amount '$\Delta \phi$' in time '$\Delta \mathrm{t}$'. The total quantity of induced electric charge '$\mathrm{Q}$' is

Accepted Answer

By Faraday's law, $\mathrm{e}=\frac{\Delta \phi}{\Delta \mathrm{t}}$
$\begin{aligned}
& 	herefore \mathrm{i}=\frac{\mathrm{e}}{\mathrm{R}}=\frac{\Delta \phi}{\mathrm{R} \Delta \mathrm{t}} \
& 	herefore(\mathrm{i} \Delta \mathrm{t})=\frac{\Delta \phi}{\mathrm{R}} \quad 	ext{..... (1)}
\end{aligned}$
But $\mathrm{i}=\frac{\Delta \mathrm{Q}}{\Delta \mathrm{t}} \quad 	herefore \Delta \mathrm{Q}=\mathrm{i} \Delta \mathrm{t}$
$\begin{aligned}
& 	herefore 	ext { From (1), } \Delta Q=\frac{\Delta \phi}{\mathrm{R}} \
& 	herefore \mathrm{Q}=\frac{\Delta \phi}{\mathrm{R}}
\end{aligned}$

Answer

$-\frac{\Delta \phi}{\Delta \mathrm{t}}+\mathrm{R}$

Answer

$\frac{\Delta \phi}{\Delta \mathrm{t}} 	imes \mathrm{R}$

Answer

$\frac{\Delta \phi}{\mathrm{R}}$

Answer

$\frac{\Delta \phi}{\Delta t}$

Electromagnetic Induction

The magnetic flux through a coil of resistance 'R' changes by an amount '\Delta \phi' in time '\Delta \mathrm{t}'. The total quantity of induced electric charge '\mathrm{Q}' is

Choose the correct answer: