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Class 12 • Physics • Chapter-1
Electrostatics & Capacitance
Question 362 of 858
362
Easy
JEE Mains
2022
A vertical electric field of magnitude 4.9 $
\times
$ 10 5 N/C just prevents a water droplet of a mass 0.1 g from falling. The value of charge on the droplet will be : (Given : g = 9.8 m/s 2 )
Choose the correct answer:
A
1.6 $
\times
10
-
$9 C
B
2.0 $
\times
10
-
$9 C
C
3.2 $
\times
10
-
$9 C
D
0.5 $
\times
10
-
$9 C
Select an answer first
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