Question 283: Electrostatics & Capacitance

Question

A capacitor of capacitance C = 1 $$\mu$$F is suddenly connected to a battery of 100 volt through a resistance R = 100 $$\Omega$$. The time taken for the capacitor to be charged to get 50 V is :
[Take ln 2 = 0.69]

Accepted Answer

$$V = {V_0}\left( {1 - {e^{ - {t \over {RC}}}}} ight)$$
$$50 = 100\left( {1 - {e^{ - {t \over {RC}}}}} ight)$$
$$ = t = 0.69 	imes {10^{ - 4}}$$ sec.

Answer

1.44 $$	imes$$ 10
$$-$$4
s

Answer

3.33 $$	imes$$ 10
$$-$$4
s

Answer

0.69 $$	imes$$ 10
$$-$$4
s

Answer

0.30 $$	imes$$ 10
$$-$$4
s

Electrostatics & Capacitance

A capacitor of capacitance C = 1 $\muF is suddenly connected to a battery of 100 volt through a resistance R = 100 \Omega$. The time taken for the capacitor to be charged to get 50 V is : [Take ln 2 = 0.69]

Choose the correct answer: