Question 783: Electrostatics & Capacitance

Question

In given situation, force on charge $Q_3$ is

Accepted Answer

We are asked to find the net force acting on charge $ Q_3 $.
Using CoulombÃ¢ÂÂs law, the force on $ Q_3 $ due to $ Q_1 $ is
$$ F_{31} = \frac{9 	imes 10^9 	imes 6.5 	imes 10^{-5} 	imes 8.6 	imes 10^{-5}}{(0.6)^2} = 140~\mathrm{N} $$
The force on $ Q_3 $ due to $ Q_2 $ is given as $ F_{32} = 330~\mathrm{N} $.
Resolving $ F_{31} $ into components:
Along the X-axis:
$$ F_{31x} = F_{31} \cos 30^\circ = 120~\mathrm{N} $$
Along the Y-axis:
$$ F_{31y} = -F_{31} \sin 30^\circ = -70~\mathrm{N} $$
Finding the net force on $ Q_3 $:
The total force on $ Q_3 $ is obtained by combining the components along X and Y axes:
$$ F_3 = \sqrt{F_x^2 + F_y^2} = 290~\mathrm{N} $$

Answer

140 N

Answer

330 N

Answer

120 N

Answer

290 N

Electrostatics & Capacitance

In given situation, force on charge Q_3 is

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