Question 156: Electrostatics & Capacitance

Question

A 2$$\mu$$F capacitor C
1
is first charged to a potential difference of 10V using a battery. Then the battery is removed and the capacitor is connected to an uncharged capacitor C
2
of 8 $$\mu$$F. The charge in C
2
on equilibrium condition is ____________ $$\mu$$C. (Round off to the Nearest Integer)

Accepted Answer

When battery is removed & the capacitor is connected
2V + 8v = 20
10V = 20
V = 2 volt
$$ \because $$ Q = CV
Q = 8 $$	imes$$ 2 = 16$$\mu$$c

Electrostatics & Capacitance

A 2$\muF capacitor C 1 is first charged to a potential difference of 10V using a battery. Then the battery is removed and the capacitor is connected to an uncharged capacitor C 2 of 8 \muF. The charge in C 2 on equilibrium condition is ____________ \mu$C. (Round off to the Nearest Integer)

Integer / Numeric Answer Type