Question 142: Electrostatics & Capacitance

Question

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason $\mathbf{R}$
Assertion A :
In electrostatics, a conductor does not store any net charge inside.
Reason R :
Inside the capacitor (with no dielectric medium), the free charge carriers, if placed between the plates of capacitor, experience force and drift.
Choose the correct answer from the options given below

Accepted Answer

The correct option is
Option B
.
Step-by-step reasoning:
Assertion A:
Ã¢ÂÂIn electrostatics, a conductor does not store any net charge inside.Ã¢ÂÂ
This is
true
.
According to electrostatic equilibrium:
The electric field inside a conductor is zero.
Any excess charge given to a conductor resides only on its
outer surface
.
Therefore, there is
no net charge inside the bulk of the conductor
.
So,
Assertion A is true
.
Reason R:
Ã¢ÂÂInside the capacitor (with no dielectric medium), the free charge carriers, if placed between the plates of capacitor, experience force and drift.Ã¢ÂÂ
This is also
true
.
Between the plates of a capacitor, there is an electric field. If a free charge carrier is placed there, it experiences an electric force:
$$ F = qE $$
Hence it will drift in the direction of the force.
So,
Reason R is true
.
But does R explain A?
No.
Assertion A is about the behavior of charge
inside a conductor in electrostatic equilibrium
.
Reason R is about the behavior of a
free charge placed in the electric field between capacitor plates
.
These are two different situations.
So, although both statements are true,
R is not the correct explanation of A
.
Final Answer:
$$ \boxed{	ext{Option B}} $$
Both $A$ and $R$ are true, but $R$ is
not
the correct explanation of $A$.

Answer

Both $\mathbf{A}$ and $\mathbf{R}$ are true and $\mathbf{R}$ is the correct explanation of $\mathbf{A}$

Answer

Both $\mathbf{A}$ and $\mathbf{R}$ are true but $\mathbf{R}$ is NOT the correct explanation of $\mathbf{A}$

Answer

A is true but $\mathbf{R}$ is false

Answer

A is false but $\mathbf{R}$ is true

Electrostatics & Capacitance

Choose the correct answer: