Question 60: Electrostatics & Capacitance

Question

The electric field versus distance graph is shown as given. Select the correct statement from the following.
E- electric field
R-radius
r - distance from the centre

Accepted Answer

Electric flux ÃÂ is defined as the electric field E times an area A. Its dimensions follow from:
Ã¢ÂÂ¢  Electric field
$$E = \frac{F}{q}$$
with
Ã¢ÂÂ Force: $$[F]=M\,L\,T^{-2}$$
Ã¢ÂÂ Charge: $$[q]=A\,T$$
so
$$[E]=\frac{M\,L\,T^{-2}}{A\,T}=M\,L\,T^{-3}\,A^{-1}$$
Ã¢ÂÂ¢  Flux
$$\phi = E	imes A$$
with area $$[A]=L^2$$ gives
$$[\phi]=\bigl(M\,L\,T^{-3}\,A^{-1}\bigr)	imes L^2 = M\,L^3\,T^{-3}\,A^{-1}$$
That matches Option D.

Answer

The graph shows the variation of the electric field intensity with distance from the centre of a uniformly charged conducting ring of radius R.

Answer

The graph shows the variation of the electric field intensity with distance from the centre of a uniformly charged non conducting solid sphere of radius R.

Answer

The graph shows the variation of the electric field intensity with distance from the centre of a uniformly charged conducting solid sphere of radius R.

Answer

The graph shows the variation of the electric field intensity with distance from the centre of a uniformly charged non conducting cylinder of radius R.

Electrostatics & Capacitance

The electric field versus distance graph is shown as given. Select the correct statement from the following. E- electric field R-radius r - distance from the centre

Choose the correct answer: