Question 60: Electrostatics & Capacitance

Question

The electric field versus distance graph is shown as given. Select the correct statement from the following.
E- electric field
R-radius
r - distance from the centre
![](https://app-content.cdn.examgoal.net/fly/@width/image/jaoe38c1mdt34qur/022c0398-96ab-48f6-9334-43f499d30351/31b9c430-6efb-11f0-9c80-fb630be8a857/file-jaoe38c1mdt34qus.png?format=png)

Accepted Answer

Electric flux ÃÂ is defined as the electric field E times an area A. Its dimensions follow from:
Ã¢ÂÂ¢  Electric field
$E = \frac{F}{q}$
with
Ã¢ÂÂ Force: $[F]=M\,L\,T^{-2}$
Ã¢ÂÂ Charge: $[q]=A\,T$
so
$[E]=\frac{M\,L\,T^{-2}}{A\,T}=M\,L\,T^{-3}\,A^{-1}$
Ã¢ÂÂ¢  Flux
$\phi = E	imes A$
with area $[A]=L^2$ gives
$[\phi]=\bigl(M\,L\,T^{-3}\,A^{-1}\bigr)	imes L^2 = M\,L^3\,T^{-3}\,A^{-1}$
That matches Option D.

Answer

The graph shows the variation of the electric field intensity with distance from the centre of a uniformly charged conducting ring of radius R.

Answer

The graph shows the variation of the electric field intensity with distance from the centre of a uniformly charged non conducting solid sphere of radius R.

Answer

The graph shows the variation of the electric field intensity with distance from the centre of a uniformly charged conducting solid sphere of radius R.

Answer

The graph shows the variation of the electric field intensity with distance from the centre of a uniformly charged non conducting cylinder of radius R.

Electrostatics & Capacitance

The electric field versus distance graph is shown as given. Select the correct statement from the following. E- electric field R-radius r - distance from the centre

Choose the correct answer: