Question 427: Electrostatics & Capacitance

Question

Five capacitors, each of capacity ' $C$ ' are connected as shown in the figure. The resultant capacity between A and B is $14 \mu \mathrm{~F}$. The capacity of each capacitor is

Accepted Answer

$C_1, C_2 \& C_3$ are in parallel, whereas $C_4$ and $C_5$ are in series.
$$ \begin{array}{ll} 	herefore & \mathrm{C}_{	ext {eq1 }}=\mathrm{C}_1+\mathrm{C}_2+\mathrm{C}_3=3 \mathrm{C} \ 	herefore & \mathrm{C}_{	ext {eq2 }}=\frac{1}{\mathrm{C}_4}+\frac{1}{\mathrm{C}_5}=\frac{\mathrm{C}}{2} \end{array} $$
$\mathrm{C}_{	ext {eq }}$ is in parallel with $\mathrm{C}_{	ext {eq } 2}$
$$ \begin{aligned} 	herefore \quad \mathrm{C}_{\mathrm{eq}} & =\mathrm{C}_{\mathrm{eq} 1}+\mathrm{C}_{\mathrm{eq} 2} \ \mathrm{C}_{\mathrm{eq}} & =\frac{7}{2} \mathrm{C} \end{aligned} $$
Now we know,
$$ \begin{aligned} & \mathrm{C}_{\mathrm{eq}}=14 \mu \mathrm{~F} \ 	herefore & \frac{7}{2} \mathrm{C}=14 \mu \mathrm{~F} \ 	herefore & \mathrm{C}=4 \mu \mathrm{~F} \end{aligned} $$

Answer

$2 \mu \mathrm{~F}$

Answer

$3.5 \mu \mathrm{~F}$

Answer

$4 \mu \mathrm{~F}$

Answer

$2.8 \mu \mathrm{~F}$

Electrostatics & Capacitance

Five capacitors, each of capacity ' C ' are connected as shown in the figure. The resultant capacity between A and B is 14 \mu \mathrm{~F}. The capacity of each capacitor is

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