Question 766: Electrostatics & Capacitance

Question

The electric potential at a point in free space due to charge Q coulomb is Q $ 	imes $ 10
11
volts. The electric field at that point is

Accepted Answer

$V = {1 \over {4\pi {\varepsilon _0}}} 	imes {Q \over R}$
= Q ÃÂ 10
11
volt      Ã¢ÂÂ¦(i)
$E = {1 \over {4\pi {\varepsilon _0}}} 	imes {Q \over {{R^2}}}$
= V/R = Q ÃÂ 10
11
ÃÂ ${4\pi {\varepsilon _0}}$ ÃÂ 10
11
from ...(i)
= ${4\pi {\varepsilon _0}}$  ÃÂ Q ÃÂ 10
22
volt/m

Answer

$4\pi {\varepsilon _0}Q 	imes {10^{20}}$ volt/m

Answer

12$\pi $
0
Q $ 	imes $ 10
22
volt/m

Answer

$4\pi {\varepsilon _0}Q 	imes {10^{22}}$ volt/m

Answer

$12\pi {\varepsilon _0}Q 	imes {10^{20}}$ volt/m

Electrostatics & Capacitance

The electric potential at a point in free space due to charge Q coulomb is Q \times 10 11 volts. The electric field at that point is

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