Question 379: Electrostatics & Capacitance

Question

What will be the magnitude of electric field at point O as shown in the figure? Each side of the figure is l and perpendicular to each other?
![](https://imagex.cdn.examgoal.net/1ks44m1q4/542be179-9d8b-4952-ac00-efefdb06efa3/0f2cc7c0-f8c9-11eb-a1d4-495922108aa7/file-1ks44m1q5.jpg)

Accepted Answer

${E_1} = {{kq} \over {{l^2}}} = {E_2}$
${E_3} = {{kq} \over {{{(\sqrt 2 l)}^2}}} = {{kq} \over {2{l^2}}}$
$E = {{\sqrt 2 kq} \over {{l^2}}} - {{kq} \over {2{l^2}}} = {{kq} \over {2{l^2}}}\left( {2\sqrt 2  - 1} \right)$
![](https://imagex.cdn.examgoal.net/1ks44n9x0/c29627a5-98e0-4f8a-938d-0d2f64b73d93/314fcb40-f8c9-11eb-a1d4-495922108aa7/file-1ks44n9x1.png)

Answer

${1 \over {4\pi {\varepsilon _0}}}{q \over {{l^2}}}$

Answer

${1 \over {4\pi {\varepsilon _0}}}{q \over {(2{l^2})}}\left( {2\sqrt 2  - 1} \right)$

Answer

${q \over {4\pi {\varepsilon _0}{{(2l)}^2}}}$

Answer

${1 \over {4\pi {\varepsilon _0}}}{{2q} \over {2{l^2}}}\left( {\sqrt 2 } \right)$

Electrostatics & Capacitance

What will be the magnitude of electric field at point O as shown in the figure? Each side of the figure is l and perpendicular to each other?

Choose the correct answer: