Question 102: Electrostatics & Capacitance

Question

A capacitor of capacitance $$\mathrm{C}$$ and potential $$\mathrm{V}$$ has energy $$\mathrm{E}$$. It is connected to another capacitor of capacitance $$2 \mathrm{C}$$ and potential $$2 \mathrm{~V}$$. Then the loss of energy is $$\frac{x}{3} \mathrm{E}$$, where $$x$$ is _______.

Accepted Answer

$$\begin{aligned}
& 	ext { Energy loss }=\frac{1}{2} \frac{C_1 C_2}{C_1+C_2}\left(V_1-V_2ight)^2 \
& =\frac{2}{3} \cdot E \
& 	herefore x=2
\end{aligned}$$

Electrostatics & Capacitance

A capacitor of capacitance $\mathrm{C} and potential \mathrm{V} has energy \mathrm{E}. It is connected to another capacitor of capacitance 2 \mathrm{C} and potential 2 \mathrm{~V}. Then the loss of energy is \frac{x}{3} \mathrm{E}, where x$ is _______.

Integer / Numeric Answer Type