Question 519: Electrostatics & Capacitance

Question

The equivalent capacity between terminal $$\mathrm{A}$$ and $$\mathrm{B}$$ is

Accepted Answer

$$\begin{aligned}
&\frac{1}{C_s}=\frac{1}{C}+\frac{1}{C}+\frac{1}{C} \\
&	herefore \quad C_s  =\frac{C}{3}
\end{aligned}$$
Now, $$\mathrm{C}_{\mathrm{s}}$$ and $$\mathrm{C}$$ are connected in parallel,
$$	herefore \quad \mathrm{C}_{\mathrm{net}}=\mathrm{C}_{\mathrm{s}}+\mathrm{C}=\frac{\mathrm{C}}{3}+\mathrm{C}=\frac{4 \mathrm{C}}{3}$$

Answer

$$\frac{\mathrm{C}}{4}$$

Answer

$$\frac{3 \mathrm{C}}{4}$$

Answer

$$\frac{\mathrm{C}}{3}$$

Answer

$$\frac{4 \mathrm{C}}{3}$$

Electrostatics & Capacitance

The equivalent capacity between terminal $\mathrm{A} and \mathrm{B}$ is

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