Question 316: Electrostatics & Capacitance

Question

A point charge of 10 $$\mu$$C is placed at the origin. At what location on the X-axis should a point charge of 40 $$\mu$$C be placed so that the net electric field is zero at $$x=2$$cm on the X-axis?

Accepted Answer

$$
	herefore E_{x}=2 \mathrm{~cm}=0
$$
$$
\begin{aligned}
& \frac{1}{4 \pi \varepsilon_{0}} \frac{(10 \mu \mathrm{C})}{(2 \mathrm{~cm})^{2}}=\frac{1}{4 \pi \varepsilon_{0}} \frac{(40 \mu \mathrm{C})}{[(\mathrm{a}-2) \mathrm{cm}]^{2}}
\end{aligned}
$$
$\Rightarrow\left(\frac{a-2}{2}ight)^{2}=4$
$\Rightarrow \frac{a-2}{2}=2$
$$
a=6 \mathrm{~cm}
$$

Answer

$$x=6$$ cm

Answer

$$x=8$$ cm

Answer

$$x=4$$ cm

Answer

$$x=-4$$ cm

Electrostatics & Capacitance

A point charge of 10 $\muC is placed at the origin. At what location on the X-axis should a point charge of 40 \muC be placed so that the net electric field is zero at x=2$cm on the X-axis?

Choose the correct answer: