Question 490: Electrostatics & Capacitance

Question

For a uniformly charged ring of radius R, the electric field on its axis has the largest magnitude  at a distance h from its center. Then value of h is :

Accepted Answer

Electric field on the axis of the ring,
$$E = {{KQh} \over {{{\left( {{R^2} + {h^2}} \right)}^{{3 \over 2}}}}}$$
For maximum electric field,
$${{dE} \over {dh}} = 0$$
$$ \Rightarrow $$   $$h = {R \over {\sqrt 2 }}$$

Answer

$${R \over {\sqrt 5 }}$$

Answer

$${R \over {\sqrt 2 }}$$

Answer

R

Answer

R$$\sqrt 2 $$

Electrostatics & Capacitance

For a uniformly charged ring of radius R, the electric field on its axis has the largest magnitude at a distance h from its center. Then value of h is :

Choose the correct answer: