Question 321: Electrostatics & Capacitance

Question

In the given circuit, the charge on 4 $$\mu $$F capacitor will be :

Accepted Answer

As V = $${q \over C}$$
$$ 	herefore $$ V $$ \propto $$ $${1 \over C}$$
So $${{{V_1}} \over {{V_2}}} = {{{C_2}} \over {{C_1}}}$$
$$ \Rightarrow $$ $${{{V_1}} \over {{V_2}}} = {6 \over 4} = {3 \over 2}$$
Also V
1
+ V
2
= 10
$$ 	herefore $$ V
1
+ $${2 \over 3}$$V
1
= 10
$$ \Rightarrow $$ $${{5{V_1}} \over 3}$$ = 10
$$ \Rightarrow $$ V
1
= 6 V
The charge on 4 $$\mu $$F capacitor is = C
1
V
1
= 4 $$ 	imes $$ 6 = 24 $$\mu $$C

Answer

5.4 $$\mu $$C

Answer

9.6 $$\mu $$C

Answer

13.4 $$\mu $$C

Answer

24 $$\mu $$C

Electrostatics & Capacitance

In the given circuit, the charge on 4 $\mu $F capacitor will be :

Choose the correct answer: