Question 62: Electrostatics & Capacitance

Question

What is the dimensional formula for electric flux?

Accepted Answer

Electric flux ÃÂ is defined as the electric field E times an area A. Its dimensions follow from:
Ã¢ÂÂ¢  Electric field
$$E = \frac{F}{q}$$
with
Ã¢ÂÂ Force: $$[F]=M\,L\,T^{-2}$$
Ã¢ÂÂ Charge: $$[q]=A\,T$$
so
$$[E]=\frac{M\,L\,T^{-2}}{A\,T}=M\,L\,T^{-3}\,A^{-1}$$
Ã¢ÂÂ¢  Flux
$$\phi = E	imes A$$
with area $$[A]=L^2$$ gives
$$[\phi]=\bigl(M\,L\,T^{-3}\,A^{-1}\bigr)	imes L^2 = M\,L^3\,T^{-3}\,A^{-1}$$
That matches Option D.

Answer

$\left[\mathrm{M}^1 \mathrm{~L}^3 \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right]$

Answer

$\left[\mathrm{M}^2 \mathrm{~L}^3 \mathrm{~T}^{-3} \mathrm{~A}^{-1}\right]$

Answer

$\left[\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-3} \mathrm{~A}^{-1}\right]$

Answer

$\left[\mathrm{M}^1 \mathrm{~L}^3 \mathrm{~T}^{-3} \mathrm{~A}^{-1}\right]$

Electrostatics & Capacitance

What is the dimensional formula for electric flux?

Choose the correct answer: