Question 318: Electrostatics & Capacitance

Question

The electric potential at the centre of two concentric half rings of radii R$$_1$$ and R$$_2$$, having same linear charge density $$\lambda$$ is :

Accepted Answer

$V_{1}=\frac{1}{4 \pi \varepsilon_{0}} 	imes \frac{\lambda\left(\pi R_{1}ight)}{R_{1}}$
$$
\begin{aligned}
V_{2}= & \frac{1}{4 \pi \varepsilon_{0}} 	imes \frac{\lambda\left(\pi R_{2}ight)}{R_{2}} \\
V_{	ext {net }} & =V_{1}+V_{2} \\
& =2 	imes \frac{1}{4 \pi \varepsilon_{0}} \pi \lambda \\
& =\frac{\lambda}{2 \varepsilon_{0}}
\end{aligned}
$$

Answer

$$\frac{\lambda}{2\in_0}$$

Answer

$$\frac{\lambda}{\in_0}$$

Answer

$$\frac{2\lambda}{\in_0}$$

Answer

$$\frac{\lambda}{4\in_0}$$

Electrostatics & Capacitance

The electric potential at the centre of two concentric half rings of radii R$_1 and R_2, having same linear charge density \lambda$ is :

Choose the correct answer: