Question 418: Electrostatics & Capacitance

Question

Two charged thin infinite plane sheets of
uniform surface charge density $${\sigma _ + }$$ and $${\sigma _ - }$$,
where |$${\sigma _ + }$$| > |$${\sigma _ - }$$|, intersect at right angle.
Which of the following best represents the
electric field lines for this system :

Accepted Answer

Given, |$${\sigma _ + }$$| > |$${\sigma _ - }$$|
We know, $$\left| {{E_ + }} ight| = {{\left| {{\sigma _ + }} ight|} \over {{\varepsilon _0}}}$$
and $$\left| {{E_ - }} ight| = {{\left| {{\sigma _ - }} ight|} \over {{\varepsilon _0}}}$$
$$ 	herefore $$ $$\left| {{E_ + }} ight|$$ > $$\left| {{E_ - }} ight|$$
Thin infinite uniformly charged planes produces uniform electric field therefore option A and C are obviously
wrong.
And as positive charge density is bigger in magnitude so its field along Y direction will be bigger than field
of negative charge in X direction and this is evident in option B so it is correct.

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Electrostatics & Capacitance

Two charged thin infinite plane sheets of uniform surface charge density ${\sigma _ + } and {\sigma _ - }, where |{\sigma _ + }| > |{\sigma _ - }$|, intersect at right angle. Which of the following best represents the electric field lines for this system :

Choose the correct answer: