Question 27: Electrostatics & Capacitance

Question

The separation between two parallel plates of capacitor is 1 mm. What is the electric potential generates between the plates of capacitor, when electric field of 2000 N/C is applied on it?

Accepted Answer

In a uniform electric field, potential difference across two parallel plates of capacitor,
$$V = Ed$$
where, E is electric field and d is separation between plates.
$$ \Rightarrow V = 2000 	imes (1 	imes {10^{ - 3}}) = 2V$$

Answer

2 V

Answer

2000 V

Answer

0.2 V

Answer

200 V

Electrostatics & Capacitance

The separation between two parallel plates of capacitor is 1 mm. What is the electric potential generates between the plates of capacitor, when electric field of 2000 N/C is applied on it?

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