Question 805: Electrostatics & Capacitance

Question

Consider an electric field $$\overrightarrow E  = {E_0}\widehat x$$ where $${E_0}$$ is a constant. The flux through the shaded area (as shown in the figure)  due to this field is

Accepted Answer

The flux through an area $$\overrightarrow S $$ due to an electric field $$\overrightarrow E $$ is given by
$$\phi  = \oint {\overrightarrow E \,.\,d\overrightarrow S } $$
$$ = \overrightarrow E \,.\,\oint {d\overrightarrow S  = \overrightarrow E \,.\,\overrightarrow S } $$ ($$\because$$ $$\overrightarrow E $$ is a constant.) ...... (1)
The area of the shaded region is the cross product of vectors representing the two sides i.e.,
$$\overrightarrow S  = (a\widehat j) 	imes (a\widehat i + a\widehat k) = {a^2}(\widehat i - \widehat k)$$ ...... (2)
Use equations (1) and (2) to get
$$\phi  = ({E_0}\widehat i)\,.\,{a^2}(\widehat i - \widehat k) = {E_0}{a^2}$$.

Answer

$$2{E_0}{a_2}$$

Answer

$$\sqrt 2 {E_0}{a^2}$$

Answer

$${E_0}\,{a^2}$$

Answer

$${{{E_0}{a^2}} \over {\sqrt 2 }}$$

Electrostatics & Capacitance

Consider an electric field $\overrightarrow E = {E_0}\widehat x where {E_0}$ is a constant. The flux through the shaded area (as shown in the figure) due to this field is

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