Question 336: Electrostatics & Capacitance

Question

Voltage rating of a parallel plate capacitor is
500V. Its dielectric can withstand a maximum
electric field of 10
6
V/m. The plate area is
10
–4
m
2
. What is the dielectric constant is the
capacitance is 15 pF?
(given $$\varepsilon $$
0
= 8.86 × 10
–12
C
2
/Nm
2
)

Accepted Answer

A = 10
Ã¢ÂÂ4
m
2
E
max
= 10
6
V/m
C = 15 $$\mu $$F
$$C = {{k{\varepsilon _0}A} \over d};{{Cd} \over {{\varepsilon _0}A}} = k$$
$$k = {{15 	imes {{10}^{ - 12}} 	imes 500 	imes {{10}^{ - 6}}} \over {8.86 	imes {{10}^{ - 12}} 	imes {{10}^4}}}$$
= $${{15 	imes 5} \over {8.86}} = 8.465$$
k $$ \approx $$ 8.5

Answer

8.5

Answer

4.5

Answer

3.8

Answer

6.2

Electrostatics & Capacitance

Voltage rating of a parallel plate capacitor is 500V. Its dielectric can withstand a maximum electric field of 10 6 V/m. The plate area is 10 –4 m 2 . What is the dielectric constant is the capacitance is 15 pF? (given $\varepsilon $ 0 = 8.86 × 10 –12 C 2 /Nm 2 )

Choose the correct answer: