Question 145: Electrostatics & Capacitance

Question

A capacitor of capacitance 50 pF is charged by 100 V source. It is then connected to another uncharged identical capacitor. Electrostatic energy loss in the process is ___________ nJ.

Accepted Answer

Electrical energy lost $$ = {1 \over 2}\left( {{1 \over 2}C{V^2}} ight)$$
$$ = {1 \over 2} 	imes {1 \over 2} 	imes 50 	imes {10^{ - 12}} 	imes {(100)^2}$$
$$ = {{500} \over 4}$$ nJ
$$ = 125$$ nJ

Electrostatics & Capacitance

A capacitor of capacitance 50 pF is charged by 100 V source. It is then connected to another uncharged identical capacitor. Electrostatic energy loss in the process is ___________ nJ.

Integer / Numeric Answer Type