Question 582: Electrostatics & Capacitance

Question

An air filled parallel plate capacitor has a capacity $2 \mathrm{~pF}$. The sepeartion of the plates is doubled and the interspace between the plates is filled with dielectric material, then the capacity is increased to $6 ~\mathrm{pF}$. The dielectric constant of the material is

Accepted Answer

$\begin{aligned} & \mathrm{C}=\frac{\mathrm{KA} \varepsilon_0}{\mathrm{~d}} \ & 	herefore \frac{\mathrm{C}_2}{\mathrm{C}_1}=\frac{\mathrm{k}_2}{\mathrm{k}_1} \cdot \frac{\mathrm{d}_1}{\mathrm{~d}_2}\end{aligned}$
$\begin{aligned} & 	herefore \frac{6}{2}=\frac{\mathrm{k}_2}{1} \cdot \frac{1}{2} \ & 	herefore \mathrm{k}_2=6\end{aligned}$

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3

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6

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2

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4

Electrostatics & Capacitance

An air filled parallel plate capacitor has a capacity 2 \mathrm{~pF}. The sepeartion of the plates is doubled and the interspace between the plates is filled with dielectric material, then the capacity is increased to 6 ~\mathrm{pF}. The dielectric constant of the material is

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