Question 223: Electrostatics & Capacitance

Question

An electric dipole of mass $m$, charge $q$, and length $l$ is placed in a uniform electric field $\vec{E} = E_0\hat{i}$. When the dipole is rotated slightly from its equilibrium position and released, the time period of its oscillations will be :

Accepted Answer

$$\begin{aligned}
& \mathrm{I} \omega 2 	heta=\mathrm{q} \ell \mathrm{E}_0 	heta \
& 2 \mathrm{~m}\left(\frac{\ell}{2}ight)^2 \omega^2=\mathrm{q} \ell \mathrm{E}_0 \
& \omega^2=\frac{2 \mathrm{qE}_0}{\mathrm{~m} \ell} \
& \mathrm{~T}=2 \pi \sqrt{\frac{\mathrm{~m} \ell}{2 \mathrm{qE}_0}}
\end{aligned}$$

Answer

$ \frac{1}{2\pi} \sqrt{\frac{ml}{2qE_0}} $

Answer

$ 2\pi \sqrt{\frac{ml}{2qE_0}} $

Answer

$ 2\pi \sqrt{\frac{ml}{qE_0}} $

Answer

$\frac{1}{2 \pi} \sqrt{\frac{2 \mathrm{~m} l}{\mathrm{q} \mathrm{E}_0}}$

Electrostatics & Capacitance

An electric dipole of mass m, charge q, and length l is placed in a uniform electric field \vec{E} = E_0\hat{i}. When the dipole is rotated slightly from its equilibrium position and released, the time period of its oscillations will be :

Choose the correct answer: