Question 94: Electrostatics & Capacitance

Question

Three capacitors of capacitances $$25 \mu \mathrm{F}, 30 \mu \mathrm{F}$$ and $$45 \mu \mathrm{F}$$ are connected in parallel to a supply of $$100 \mathrm{~V}$$. Energy stored in the above combination is E. When these capacitors are connected in series to the same supply, the stored energy is $$\frac{9}{x} \mathrm{E}$$. The value of $$x$$ is _________.

Accepted Answer

$$E=\frac{1}{2}(25+30+45)(100)^2 \quad 	ext{.... (i)}$$
$$	ext { Also, } \frac{9}{x} E=\frac{1}{2} \frac{1}{\left(\frac{1}{25}+\frac{1}{30}+\frac{1}{45}ight)}(100)^2 \quad 	ext{.... (ii)}$$
From (i) and (ii)
$$x=86$$

Electrostatics & Capacitance

Integer / Numeric Answer Type