Question 641: Electrostatics & Capacitance

Question

A parallel plate air capacitor has capacity C, distance of separation between plates is d and potential difference $$V$$ is applied between the plates. Force of attraction between the plates of the parallel plate air capacitor is

Accepted Answer

Force of attraction between the plates, F = qE
$$ = q 	imes {\sigma  \over {2{ \in _0}}} = q{q \over {2A{ \in _0}}}$$
$$ = {{{q^2}} \over {2\left( {{{{ \in _0}A} \over d}} ight) 	imes d}} = {{{C^2}{V^2}} \over {2cd}} = {{C{V^2}} \over {2d}}$$
Here, $$C = {{{ \in _0}A} \over d}$$, $$q = CV$$, A = area

Answer

$${{C{V^2}} \over d}$$

Answer

$${{{C^2}{V^2}} \over {2{d^2}}}$$

Answer

$${{{C^2}{V^2}} \over {2d}}$$

Answer

$${{C{V^2}} \over {2d}}$$

Electrostatics & Capacitance

A parallel plate air capacitor has capacity C, distance of separation between plates is d and potential difference $V$ is applied between the plates. Force of attraction between the plates of the parallel plate air capacitor is

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