Question 668: Electrostatics & Capacitance

Question

Energy per unit volume for a capacitor having area A and  separation d kept at potential difference V is given by

Accepted Answer

Energy stored per unit volume
$$ = {1 \over 2}{\varepsilon _0}{E^2} = {1 \over 2}{\varepsilon _0}{\left( {{V \over d}} \right)^2} = {1 \over 2}{\varepsilon _0}{{{V^2}} \over {{d^2}}}$$
$$\left(\because {E = {V \over d}} \right)$$

Answer

$${1 \over 2}{\varepsilon _0}{{{V^2}} \over {{d^2}}}$$

Answer

$${1 \over {2{\varepsilon _0}}}{{{V^2}} \over {{d^2}}}$$

Answer

$${1 \over 2}C{V^2}$$

Answer

$${{{Q^2}} \over {2C}}.$$

Electrostatics & Capacitance

Energy per unit volume for a capacitor having area A and separation d kept at potential difference V is given by

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