Question 419: Gravitation

Question

For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is

Accepted Answer

K.E. of satellite moving in an orbit around the earth  is
$$K = {1 \over 2}m{v^2} = {1 \over 2}m{\left( {\sqrt {{{GM} \over r}} } \right)^2} = {{GMm} \over {2r}}$$
P.E. of satellite and earth system is
$$U = {{GMm} \over r}$$
$$ \Rightarrow {K \over U} = {{{{GMm} \over {2r}}} \over {{{GMm} \over r}}} = {1 \over 2}$$

Answer

1/2

Answer

1/$$\sqrt 2 $$

Answer

2

Answer

$$\sqrt 2 $$

Gravitation

For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is

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