Question 419: Gravitation

Question

For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is

Accepted Answer

K.E. of satellite moving in an orbit around the earth  is
$K = {1 \over 2}m{v^2} = {1 \over 2}m{\left( {\sqrt {{{GM} \over r}} } \right)^2} = {{GMm} \over {2r}}$
P.E. of satellite and earth system is
$U = {{GMm} \over r}$
$ \Rightarrow {K \over U} = {{{{GMm} \over {2r}}} \over {{{GMm} \over r}}} = {1 \over 2}$

Answer

1/2

Answer

1/$\sqrt 2 $

Answer

2

Answer

$\sqrt 2 $

Gravitation

For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is

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