Question 113: Gravitation

Question

Two particles of equal mass '$m$' move in a circle of radius '$r$' under the action of their mutual gravitational attraction. The speed of each particle will be :

Accepted Answer

$\frac{\mathrm{Gm}^{2}}{4 \mathrm{r}^{2}}=\frac{\mathrm{mv}^{2}}{\mathrm{r}}$
$
v=\sqrt{\frac{G m}{4 r}}
$

Answer

$\sqrt{\frac{G m}{4 r}}$

Answer

$\sqrt{\frac{G m}{2 r}}$

Answer

$\sqrt{\frac{G m}{r}}$

Answer

$\sqrt{\frac{4 G m}{r}}$

Gravitation

Two particles of equal mass 'm' move in a circle of radius 'r' under the action of their mutual gravitational attraction. The speed of each particle will be :

Choose the correct answer: