Question 406: Gravitation

Question

A geostationary satellite is orbiting the earth at a height of 5R above the surface of the earth, R being the radius of the earth. The time period of another satellite in  hours at a height of 2R from the surface of the earth is

Accepted Answer

According to KelpnerÃ¢ÂÂs law of period T
2
$$ \propto $$ R
3
$${{T_1^2} \over {T_2^2}} = {{R_1^3} \over {R_2^3}} = {{{{\left( {6R} ight)}^3}} \over {{{\left( {3R} ight)}^3}}} = 8$$
$${{24 	imes 24} \over {T_2^2}} = 8$$
$$T_2^2 = {{24 	imes 24} \over 8} = 72 = 36 	imes 2$$
$$ 	herefore $$ $${T_2} = 6\sqrt 2 $$

Answer

5

Answer

10

Answer

6$$\sqrt 2 $$

Answer

$${6 \over {\sqrt 2 }}$$

Gravitation

A geostationary satellite is orbiting the earth at a height of 5R above the surface of the earth, R being the radius of the earth. The time period of another satellite in hours at a height of 2R from the surface of the earth is

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