Question 169: Gravitation

Question

Consider two satellites S
1
and S
2
with periods of revolution 1 hr. and 8 hr. respectively revolving around a planet in circular orbits. The ratio of angular velocity of satellite S
1
to the angular velocity of satellite S
2
is :

Accepted Answer

Given, period of revolution of first satellite,
T
1
= 1h
Period of revolution of second satellite,
T
2
= 8h
$$	herefore$$ $${{{T_1}} \over {{T_2}}} = {1 \over 8}$$
We know that, $$\omega  = {{2\pi } \over T}$$
$$ \Rightarrow \omega  \propto {1 \over T}$$
$$\because$$ $${{{\omega _1}} \over {{\omega _2}}} = {{{T_2}} \over {{T_1}}} \Rightarrow {{{\omega _1}} \over {{\omega _2}}} = {8 \over 1}$$
or $${\omega _1}:{\omega _2} = 8:1$$

Answer

1 : 4

Answer

8 : 1

Answer

2 : 1

Answer

1 : 8

Gravitation

Consider two satellites S 1 and S 2 with periods of revolution 1 hr. and 8 hr. respectively revolving around a planet in circular orbits. The ratio of angular velocity of satellite S 1 to the angular velocity of satellite S 2 is :

Choose the correct answer: