Question 170: Laws of Motion

Question

Two masses $${m_1} = 5kg$$ and $${m_2} = 4.8kg$$ tied to a string are hanging over a light frictionless pulley. What is the acceleration of the masses when left free to move? $$\left( {g = 9.8m/{s^2}} \right)$$

Accepted Answer

For m
1
mass :
m
1
g - T = m
1
a    .........(1)
For m
2
mass :
T - m
2
g = m
2
a  ....... (2)
By solving (1) and (2) we get,
Acceleration a = $$\left( {{{{m_1} - {m_2}} \over {{m_1} + {m_2}}}} ight)g$$
$$ = {{\left( {5 - 4.8} ight) 	imes 9.8} \over {\left( {5 + 4.8} ight)}}m/{s^2}$$ = 0.2 m/s
2

Answer

$$5\,\,m/{s^2}$$

Answer

$$9.8\,\,m/{s^2}$$

Answer

$$0.2\,\,m/{s^2}$$

Answer

$$4.8\,\,m/{s^2}$$

Laws of Motion

Two masses ${m_1} = 5kg and {m_2} = 4.8kg tied to a string are hanging over a light frictionless pulley. What is the acceleration of the masses when left free to move? \left( {g = 9.8m/{s^2}} \right)

Choose the correct answer: