Question 284: Laws of Motion

Question

Two blocks A and B of masses $2 m$ and $m$, respectively, are connected by a massless and inextensible string. The whole system is suspended by a massless spring as shown in the figure. The magnitudes of acceleration of A and B, immediately after the string is cut, are respectively,

Accepted Answer

Two blocks A and B of mass 2 m and m respectively are connected by a massless and in extensible string.
The equilibrium condition FBD of 2 m
$$ k x=\mathrm{T}+2 m g=m g+2 m g=3 m g $$
After the string is cut.
$$ \mathrm{T}=0 $$
FBD of $2 m, a_2=\frac{3 m g-2 m g}{2 m}=\frac{m g}{2 m}=\frac{g}{2}$
FBD of $m, m a_1=m g=\mathrm{T}$
$$ 	herefore  a_1=g $$

Answer

$g, g / 2$

Answer

$g / 2, g$

Answer

$g, g$

Answer

$\frac{g}{2}, \frac{g}{2}$

Laws of Motion

Two blocks A and B of masses 2 m and m, respectively, are connected by a massless and inextensible string. The whole system is suspended by a massless spring as shown in the figure. The magnitudes of acceleration of A and B, immediately after the string is cut, are respectively,

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