Question 280: Laws of Motion

Question

A small block of mass M moves on a frictionless surface of an inclined plane, as shown in figure. The angle of the incline suddenly changes from 60$$^\circ$$ to 30$$^\circ$$ at point B. The block is initially at rest at A. Assume that collisions between the block and the incline are totally inelastic (g = 10 m/s$$^2$$).

Accepted Answer

$$v_C^2 - v_B^2 = 2as$$
$$v_C^2 - 45 = 2 	imes 10 	imes 3$$
$${v_c} = \sqrt {60 + 45}  = \sqrt {105} \,m{s^{ - 1}}$$ is the velocity of block just before leaving incline.

Answer

$$\sqrt{120}$$ m/s

Answer

$$\sqrt{105}$$ m/s

Answer

$$\sqrt{90}$$ m/s

Answer

$$\sqrt{75}$$ m/s

Laws of Motion

Choose the correct answer: