Question 140: Laws of Motion

Question

Two masses A and B, each of mass M are fixed together by a massless spring. A force acts on the mass B as shown in the figure. If the mass A starts moving away from mass B with acceleration 'a', then the acceleration of mass B will be :

Accepted Answer

Let spring force acting on the both block is F
s
.
F.B.D. of Block A
$$ 	herefore $$ F
s
= Ma ..... (i)
F.B.D. of Block B,
$$ 	herefore $$ Acceleration of Block B,
$${a_1} = {{{F_{net}}} \over M} = {{F - {F_s}} \over M} = {{F - Ma} \over M}$$

Answer

$${{MF} \over {F + Ma}}$$

Answer

$${{F + Ma} \over M}$$

Answer

$${{Ma - F} \over M}$$

Answer

$${{F - Ma} \over M}$$

Laws of Motion

Two masses A and B, each of mass M are fixed together by a massless spring. A force acts on the mass B as shown in the figure. If the mass A starts moving away from mass B with acceleration 'a', then the acceleration of mass B will be :

Choose the correct answer: