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Class 11PhysicsChapter-4

Laws of Motion

Question 146 of 300

146MediumJEE Mains2020

A mass of 10 kg is suspended by a rope of length 4 m, from the ceiling. A force F is applied horizontally at the mid point of the rope such that the top half of the rope makes an angle of 45 o with the vertical. Then F equal : (Take g = 10 ms –2 and the rope to be massless)

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