Question 217: Laws of Motion

Question

In the diagram shown, the normal reaction force between 2 kg and 1 kg is (Consider the surface, to be smooth) :
(Given g  = 10 ms
$$-$$2
)

Accepted Answer

Assuming all three blocks as system
Hence, acceleration of system
$$a = {{60 - 30 - 18} \over 6} = {{12} \over 6} = 2$$ m/s
2
$$a = 2$$ m/s
2
, upward along the incline.
Now, for 1 kg block
$$ \Rightarrow {N_{12}} - 18 - 5 = 1 	imes 2$$
$$ \Rightarrow {N_{12}} - 23 = 2$$
$$ \Rightarrow {N_{12}} = 25$$ N

Answer

10 N

Answer

25 N

Answer

39 N

Answer

6 N

Laws of Motion

In the diagram shown, the normal reaction force between 2 kg and 1 kg is (Consider the surface, to be smooth) : (Given g = 10 ms $-$2 )

Choose the correct answer: