Question 5: Laws of Motion

Question

A body of mass 5 kg is suspended by a spring
balance on an inclined plane as shown in
figure.
So, force applied on spring balance is
![](https://app-content.cdn.examgoal.net/fly/@width/image/jaoe38c1m3o05cdm/af30aa88-6978-4081-99d8-d070e009e7f0/71edc4a0-a635-11ef-a300-b723d4598e73/file-jaoe38c1m3o05cdn.png?format=png)

Accepted Answer

Acceleration of the body down the rough inclined plane $=g \sin 	heta$
$	herefore$ Force applied on spring balance
$\begin{aligned}
& =m g \sin 	heta=5 	imes 10 	imes \sin 30^{\circ} \\
& =5 	imes 10 	imes \frac{1}{2}=25 \mathrm{~N}
\end{aligned}$
![](https://app-content.cdn.examgoal.net/fly/@width/image/jaoe38c1m3o2816i/62cb0f92-52ca-41a0-b864-8ed976e7c733/8ef6f5a0-a63d-11ef-a300-b723d4598e73/file-jaoe38c1m3o2816j.png?format=png)

Answer

50 N

Answer

25 N

Answer

500 N

Answer

10 N

Laws of Motion

A body of mass 5 kg is suspended by a spring balance on an inclined plane as shown in figure. So, force applied on spring balance is

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