Question 222: Laws of Motion

Question

A block of mass m is placed on a smooth inclined
wedge ABC of inclination q as shown in the
figure. The wedge is given an acceleration ‘a’
towards the right. The relation between a and q
for the block to remain stationary on the wedge
is

Accepted Answer

At equilibrium
ma cos $$	heta $$ = mg sin $$	heta $$
$$ \Rightarrow $$ a = g tan $$	heta $$

Answer

$$a = {g \over {\cos ec	heta }}$$

Answer

$$a = {g \over {\cos ec	heta }}$$

Answer

$$a = g\cos 	heta $$

Answer

$$a = g	an 	heta $$

Laws of Motion

A block of mass m is placed on a smooth inclined wedge ABC of inclination q as shown in the figure. The wedge is given an acceleration ‘a’ towards the right. The relation between a and q for the block to remain stationary on the wedge is

Choose the correct answer: