Question 181: Laws of Motion

Question

Three identical blocks of masses $$m=2$$ $$kg$$ are drawn by a force $$F=10.2$$ $$N$$ with an acceleration of $$0.6$$ $$m{s^{ - 2}}$$ on a frictionless surface, then what is the tension (in $$N$$) in the string between the blocks $$B$$ and $$C$$?

Accepted Answer

Assume tension between block A and B is T
1
and block B and C is T
2
. Acceleration a = 0.6 m/s
2
.
For block A :
F - T
1
= ma
For block B :
T
1
- T
2
= ma
By adding both those equation we get,
F - T
2
= 2ma
T
2
= F - 2ma
T
2
= 10.2 - 2$$ 	imes $$2$$ 	imes $$0.6 = 10.2 - 2.4 = 7.8 N

Answer

$$9.2$$

Answer

$$3.4$$

Answer

$$4$$

Answer

$$7.8$$

Laws of Motion

Three identical blocks of masses $m=2 kg are drawn by a force F=10.2 N with an acceleration of 0.6 m{s^{ - 2}} on a frictionless surface, then what is the tension (in N) in the string between the blocks B and C$?

Choose the correct answer: