Question 186: Laws of Motion

Question

A mass ' M ' is suspended by a rope from a rigid support at point ' P ' as shown in figure. Another rope is tied at end ' Q ' and pulled horizontally with a force ' $F$ '. If the rope makes an angle ' $	heta$ ' with vertical then the tension in the string ' PQ ' is

Accepted Answer

Since the system is in equilibrium, the forces balance each other in both the horizontal and vertical direction.
Taking the horizontal component, we have:
$$ T \sin 	heta=F \Rightarrow T=\frac{F}{\sin 	heta} $$

Answer

$F \sin 	heta$

Answer

$\frac{F}{\sin 	heta}$

Answer

$F \cos 	heta$

Answer

$\frac{F}{\cos 	heta}$

Laws of Motion

A mass ' M ' is suspended by a rope from a rigid support at point ' P ' as shown in figure. Another rope is tied at end ' Q ' and pulled horizontally with a force ' F '. If the rope makes an angle ' \theta ' with vertical then the tension in the string ' PQ ' is

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