Question 160: Laws of Motion

Question

A rocket is fired vertically from the earth with an acceleration of 2g, where g is the
gravitational acceleration. On an inclined plane inside the rocket, making an angle $	heta $ with the horizontal, a point object of mass
m
is kept. The minimum coefficient of friction $\mu $
min
between the mass and the inclined surface such that the mass does not move is :

Accepted Answer

Rocket is moving upward with acceleration 2g and gravitation acceleration is g downward direction.
So, acceleration experienced by the point object,
= 2g $-$ ($-$ g) = 3g
At equilibrium,
N = 3mgcos$	heta $
$\mu $N = 3mgsin$	heta $
$ \Rightarrow $   $\mu $ (3mgcos$	heta $) = 3mg sin$	heta $
$ \Rightarrow $   $\mu $ = tan$	heta $

Answer

tan$	heta $

Answer

2tan$	heta $

Answer

3tan$	heta $

Answer

tan2$	heta $

Laws of Motion

Choose the correct answer: