Question 122: Magnetism and Matter

Question

A circular loop of radius $r$ is carrying current I A. The ratio of magnetic field at the center of circular loop and at a distance r from the center of the loop on its axis is :

Accepted Answer

$
\begin{aligned}
B_{P_{1}} & =\frac{\mu_{0} l}{2 r} \\
B_{P_{2}} & =\frac{\mu_{0} l r^{2}}{2\left(r^{2}+r^{2}ight)^{3 / 2}}=\frac{\mu_{0} I}{2^{5 / 2} r}
\end{aligned}
$
$
\begin{aligned}
& 	herefore \quad \frac{B_{P_{1}}}{B_{P_{2}}}=\frac{\frac{\mu_{0} I}{2 r}}{\frac{\mu_{0} I}{2^{5 / 2} r}}=\frac{2 \sqrt{2}}{1}
\end{aligned}
$

Answer

3$\sqrt2$ : 2

Answer

1 : 3$\sqrt2$

Answer

2$\sqrt2$ : 1

Answer

1 : $\sqrt2$

Magnetism and Matter

A circular loop of radius r is carrying current I A. The ratio of magnetic field at the center of circular loop and at a distance r from the center of the loop on its axis is :

Choose the correct answer: