Question 68: Motion in 2D & Vectors

Question

The maximum vertical height to which a man can throw a ball is 136 m. The maximum horizontal distance upto which he can throw the same ball is :

Accepted Answer

For vertical throw,
$$
\begin{aligned}
& h=\frac{v^{2}}{2 g} \\
& v=\sqrt{2 g h}=\sqrt{2 g 	imes 136} \quad...(1)
\end{aligned}
$$
For max range, $	heta=45^{\circ}$
$R_{\max }=\frac{v^{2}}{g}  \quad...(2)$
From (1) and (2)
$$
\begin{aligned}
R_{\max } & =\frac{v^{2}}{g}=\frac{2 g 	imes 136}{g} \\
& =272 \mathrm{~m}
\end{aligned}
$$

Answer

136 m

Answer

272 m

Answer

68 m

Answer

192 m

Motion in 2D & Vectors

The maximum vertical height to which a man can throw a ball is 136 m. The maximum horizontal distance upto which he can throw the same ball is :

Choose the correct answer: