Question 41: Motion in 2D & Vectors

Question

A vector in $x-y$ plane makes an angle of $30^{\circ}$ with $y$-axis. The magnitude of $\mathrm{y}$-component of vector is $2 \sqrt{3}$. The magnitude of $x$-component of the vector will be :

Accepted Answer

$$
\begin{aligned}
& \mathrm{A}_{\mathrm{y}}=\mathrm{A} \cos 30^{\circ}=2 \sqrt{3} \\
& \Rightarrow \mathrm{A} \frac{\sqrt{3}}{2}=2 \sqrt{3} \\
& \Rightarrow \mathrm{A}=4
\end{aligned}
$$
Now $A_x=A \sin 30^{\circ}=4 	imes \frac{1}{2}=2$

Answer

$\sqrt{3}$

Answer

2

Answer

6

Answer

$\frac{1}{\sqrt{3}}$

Motion in 2D & Vectors

A vector in x-y plane makes an angle of 30^{\circ} with y-axis. The magnitude of \mathrm{y}-component of vector is 2 \sqrt{3}. The magnitude of x-component of the vector will be :

Choose the correct answer: