Question 198: Motion in 2D & Vectors

Question

$\overrightarrow A $ and $\overrightarrow B $ are two vectors and $	heta $ is the angle between them,  if $\left| {\overrightarrow A  	imes \overrightarrow B } ight| = \sqrt 3 \left( {\overrightarrow A .\overrightarrow B } ight),$ the value of $	heta $ is

Accepted Answer

$\left| {\overrightarrow A  	imes \overrightarrow B } ight| = \sqrt 3 \left( {\overrightarrow A .\overrightarrow B } ight)$
$ 	herefore $ $AB\sin 	heta  = \sqrt 3 AB\cos 	heta $
or $	an 	heta  = \sqrt 3 $ or $	heta  = {	an ^{ - 1}}\sqrt 3  = 60^\circ $;

Answer

45
o

Answer

30
o

Answer

90
o

Answer

60
o

Motion in 2D & Vectors

\overrightarrow A $ and $\overrightarrow B $ are two vectors and $\theta $ is the angle between them, if $\left| {\overrightarrow A \times \overrightarrow B } \right| = \sqrt 3 \left( {\overrightarrow A .\overrightarrow B } \right),$ the value of $\theta $ is

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